🐢 Y 5 2X 3 Nie zgadzam się

Answer link. See a solution process below: Step 1) Solve the first equation for y: 2x + y = 3 2x - color (red) (2x) + y = 3 - color (red) (2x) 0 + y = 3 - 2x y = 3 - 2x Step 2) Substitute (3 - 2x) for y in the second equation and solve for x: x - 3y = 5 becomes: x - 3 (3 - 2x) = 5 x - (3 * 3) + (3 * 2x) = 5 x - 9 + 6x = 5 1x + 6x - 9 = 5 (1 + 6 y = -1/2x + 6 Given Information y - 2x = 3 need to find a perpendicular line to this line that passes through the point (2, 5) For starters, solve for y in the first equation. y - 2x = 3 y = 2x + 3 Now that we have the equation that is easy to read, to make a line perpendicular, the slope is ALWAYS the reciprocal. So the slope in this equation is 2x. The reciprocal, which is the absolute Explanation: Then substitute the value of x into one of the original equations to find the solution for y: Double check your solution by substituting values of x = − 2 and y = 3 into any of the original equations and see whether you get the numerical solution ( −5 or 5 ). x=-2 y=3 4x+y=-5 2x+3y=5 Rearrange the first equation for y: 4x+y=-5 The inverse of a function can be found algebraically by switching the x and y values y = 5/(2x + 3) x = 5/(2y + 3) x(2y + 3) = 5 2y + 3 = 5/x 2y = (5 - 3x)/x y = (5 - 3x)/(2x) h^-1(x) = (5 - 3x)/(2x) Here are a few things to remember when finding the inverse of a function: The y must be isolated (all alone on one side of the equation). Don't forget the h^-1(x) notation. I have been docked Get Step by Step Now. Starting at $5.00/month. Get step-by-step answers and hints for your math homework problems. Learn the basics, check your work, gain insight on different ways to solve problems. For chemistry, calculus, algebra, trigonometry, equation solving, basic math and more. Popular Problems Algebra Graph y=5/2x-3 y = 5 2 x − 3 y = 5 2 x - 3 Rewrite in slope-intercept form. Tap for more steps y = 5 2x− 3 y = 5 2 x - 3 Use the slope-intercept form to find the slope and y-intercept. Tap for more steps Slope: 5 2 5 2 y-intercept: (0,−3) ( 0, - 3) Any line can be graphed using two points. to find the zeros, we need to find the values of x which would cause y to become zero, i.e solve x for : 5(2x-1)(x+3) = 0 (divide both sides by 5) (2x-1)(x+3) = 0 . hence either. 2x-1 = 0 (add 1 to both sides) 2x = 1 (divide both sides by 2) x = 1/2 --> first zero. or . x+3 = 0 (subtract 3 from both sides) x = -3 ----> 2nd zero en el par (2;3) → 2 representa a "x" y 3 representa a las "y" en la ecuaciòn. 2x+3y=5. 3y=5-2x. y=(5-2x)/3. para saber si el par (2;3) es solución tiene que cumplir la ecuación anterior. reemplazando el primer punto. 3=(5-2(2))/3. 3=(5-4)/3. 3=1/3 esto no es lógico porque no cumple la igualdad. por lo tanto el par (2;3) no es solución de {4 x − y = 0 2 x − 3 y = 5 {4 x − y = 0 2 x − 3 y = 5 In Example 5.19 , it will take a little more work to solve one equation for x or y . Example 5.19 Algebra. Graph y=2x+4. y = 2x + 4 y = 2 x + 4. Use the slope-intercept form to find the slope and y-intercept. Tap for more steps Slope: 2 2. y-intercept: (0,4) ( 0, 4) Any line can be graphed using two points. Select two x x values, and plug them into the equation to find the corresponding y y values. Which expression is equivalent to x + y + x + y + 3(y + 5)? 2x + 5y + 5 2x + y + 30 2x + 5y + 15 2x + 3y + 10 . heart outlined. Thanks The solution (s) to a quadratic equation can be calculated using the Quadratic Formula: The "±" means we need to do a plus AND a minus, so there are normally TWO solutions ! The blue part ( b2 - 4ac) is called the "discriminant", because it can "discriminate" between the possible types of answer: when it is negative we get complex solutions. To graph the direct variation #y=5/2x#, determine two points on the line. If #x=0, y=(5/2*0)=0# Point = #(0,0)# If #x=2, y=(5/cancel 2*cancel 2/1)=5# Point = #(2,5)# Plot the two points and draw a straight line through the points. graph{y=5/2x [-7.605, 12.395, -3.345, 6.655]}r Find the equation of the line that is parallel to $ 2x + y - 2 = 0 $ and passes though the point $( 3, 1 )$. example 2: ex 2: Find the equation of the line that is perpendicular to $ y = 2x - 5 $ and passes though the point $\left( -\frac{2}{3}, -\frac{1}{4} \right)$. Rewrite in slope-intercept form. Tap for more steps y = 3 2x+ 5 y = 3 2 x + 5. Use the slope-intercept form to find the slope and y-intercept. Tap for more steps Slope: 3 2 3 2. y-intercept: (0,5) ( 0, 5) Any line can be graphed using two points. Select two x x values, and plug them into the equation to find the corresponding y y values. .